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The equation h(t)= -16t^2+864t models the path of a rocket shot into the air. After how many seconds does the rocket hit the ground?

1 Answer

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Answer:

t = 54 seconds

Explanation:

The equation that models the path of a rocket into the air is given by :


h(t)= -16t^2+864t

It is required to find the time after which the rocket will hit the ground. When it hits the ground, the height of the rocket will becomes zero. It means,

h(t) = 0

i.e.


-16t^2+864t=0\\\\16t(-t+54)=0\\\\16t=0, -t+54=0\\\\t=0\ and\ t=54\ s

It means after 54 seconds, the rocket will hit the ground.

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