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A line passes through point (4,-2) and has a slope of -5/4 in
Ax+By=C PLEASE

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standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient


(\stackrel{x_1}{4}~,~\stackrel{y_1}{-2})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{5}{4} \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-2)}=\stackrel{m}{-\cfrac{5}{4}}(x-\stackrel{x_1}{4})


y+2=-\cfrac{5}{4}x+5\implies \stackrel{\textit{multplying both sides by }\stackrel{LCD}{4}}{4(y+2)=4\left( -\cfrac{5}{4}x+5 \right)}\implies 4y+8=-5x+20 \\\\\\ 5x+4y+8=20\implies 5x+4y=12

User Kaj Hejer
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