Answer:
Step-by-step explanation:
a) The amount of tomatoes that arrive in the 5 hours between 8 a.m. and 1 p.m each day is ...
(75 T/h)(5 h) = 375 T
Processing at the rate of 25 T/h takes ...
(375 T)/(25 T/h) = 15 h
The processing unit must operate 15 hours per day to process the arriving tomatoes.
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b) The arriving tomatoes are processed at the rate of 25 T/h, so the net addition to inventory from 8 a.m. to 1 p.m. is 75 -25 = 50 T/h. Over those 5 hours, an inventory accumulates in the amount of ...
(50 T/h)(5 h) = 250 T
The maximum inventory of raw tomatoes is 250 tons.
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c) The processing unit operates 15 hours of each 24-hour day, so is operating at 15/24 = 5/8 = 62.5% of capacity.
The capacity utilization of the processing unit is 62.5%.
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d) Inventory both increases and decreases linearly, so the average inventory is half the peak inventory. Average inventory is 250/2 = 125 tons. This is processed at the rate of 25 T/h, so the amount of time the average tomato spends in inventory is ...
(125 T)/(25 T/h) = 5 h
The average tomato stays in the queue 5 hours.