Question

Please help me solve this question

Answer 1

sin(0) = opposite/hypotenuse = (3√3)/√31

cos(0) = adjacent/hypotenuse = 2/√31

tan(0) = opposite/adjacent = (3√3)/2

cot(0) = 2/(3√3)

sec(0) = 1/cos(0) = 1/(2/√31) = √31/2

Explanation:

Hypertenuse = √[2^2 + (3√3)^2] = √[4 + 27] = √31

sin(0) = opposite/hypotenuse = (3√3)/√31

cos(0) = adjacent/hypotenuse = 2/√31

tan(0) = opposite/adjacent = (3√3)/2

cot(0) = 2/(3√3)

sec(0) = 1/cos(0) = 1/(2/√31) = √31/2

I hope this helps