Question

A sample of gas occupies a volume of 120.0mL at a pressure of 0.75atm and a temperature of 295K. What will the volume be at a pressure of 1.25

atm and a temperature of 345K?

A)48mL

B)84mL

C)8mL

D)4mL

Answer 1

A) 84 mL

Step-by-step explanation:

use general gas equation P1×V1 / T1 = P2×V2/T2

rearrange the formula and solve for V2,it should give you V2= 84mL

Answer 2

`\large \boxed{\text{B) 84 mL}}`

Step-by-step explanation:

We can use the Combined Gas Laws to solve this problem .

`(p_(1)V_(1) )/(T_(1)) = (p_(2)V_(2))/(T_(2))`

Data

p₁ = 0.75 atm; V₁ = 120.0 mL; T₁ = 295 K

p₂ = 1.25 atm; V₂ = ?; T₂ = 345 K

Calculations

`\begin{array}{rcl}(p_(1)V_(1) )/(T_(1)) & = & (p_(2)V_(2))/(T_(2))\\\\\frac{\text{0.75 atm $*$ 120.0 mL}}{\text{295 K}} & = & \frac{\text{1.25 atm} * V_(2)}{\text{345 K}}\\\\\text{0.305 mL} & = & \text{0.003 523V}_(2)\\V_(2)& =& \frac{\text{0.305 mL}}{0.003523}\\\\& = & \textbf{84 mL}\\\end{array}\\\text{The new volume of the gas is $\large \boxed{\textbf{84 mL}}$}`