Question

A gas has a volume of .880 L at 295 K. What is the temperature of the gas

if its volume is reduced to .625 L., assuming the pressure remains
constant?
310. K
345K
210.K
567 K​

Answer 1

c. 210 K

Step-by-step explanation:

T2=V2T1/V1

- Hope that helps! Please let me know if you need further explanation.