Answer:
Explanation:
Usually in a problem of this sort you must supply one point through which the new line passes; here you have not yet done that.
Let's suppose that the new line, which is parallel to y=−3x+7, passes through the point (0, 2). Remembering that parallel lines have the same slope, we
write the new line as y = mx + b and replace m with -3; we also replace x with 0 and y with 2:
2 = -3(0) + b. Solving for b, we get b = 2. Thus, the desired equation of the line parallel to y=−3x+7 and passing through (0, 2) is
y = -3x + 2