Question

The volume of a gas at STP (standard temperature and pressure) is 5.34 L. What would the volume of the gas be at 1.54 atmospheres and 10.0 degrees C? (R = 0.0821 L·atm/mol·K ) *

Answer 1

`V_2=3.59L`

Step-by-step explanation:

Hello,

In this case, we can use the combined ideal gas law avoiding the usage of the universal ideal gas constant in order to understand the volume-pressure-temperature behavior at constant moles as given on the statement:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

Thus, since the temperature must be operated in absolute Kelvin units, we compute the required volume at 1.54 atm and 10.0 °C, considering that the initial STP conditions are 1 atm and 0 °C:

`V_2=(1atm*5.34L*(10.0+273))/(1.54atm*(0+273)K) \\\\V_2=3.59L`

Best regards.