Answer:
![pOH=11.2](https://img.qammunity.org/2021/formulas/chemistry/college/bftzzq0b3itchan33omufd4k1bcjahx6a7.png)
Step-by-step explanation:
Hello,
In this case, by knowing that the pOH is defined in terms of the concentration of OH⁻ as shown below:
![pOH=-log([OH^-])](https://img.qammunity.org/2021/formulas/chemistry/college/os6i8jhsq2yoevim3ewlj1jvyoxoba6pi1.png)
We directly compute with the given concentration:
![pOH=-log(6.5x10^(-12))\\\\pOH=11.2](https://img.qammunity.org/2021/formulas/chemistry/college/i4cx22m7ub7afttlj0g1n8551sqa1dcyht.png)
Moreover, fur such pOH, the pH will be:
![pH=14-11.2=2.8](https://img.qammunity.org/2021/formulas/chemistry/college/ud0j6ur8f739374t5o4ykmpiss7pt7fehw.png)
Which means that such solution is an acid solution.
Best regards.