Question

HELP PLEASE!!!! h(t) = −9.8t^2−5t + 39 Find the solutions of the quadratic function.

Answer 1

The solutions of the above equation are -2.26 and 1.75.

Explanation:

Given quadratic equation is
`h(t) = -9.8t^2-5t + 39`. It is required to find the solutions of this quadratic equation.

The general form of quadratic equation is given by :

`ax^2+bx+c=0`

The solution of equation is :

`x=(-b\pm √(b^2-4ac) )/(2a)`

On comparing the given equation,

a = -9.8, b = -5 and c = 39

Its solutions are :

`t=(-(-5)+ √((-5)^2-4* (-9.8)(39)) )/(2* (-9.8)), (-b- √(b^2-4ac) )/(2a)\\\\t=-2.26, 1.75`

So, the solutions of the above equation are -2.26 and 1.75.