434,327 views
34 votes
34 votes
Find the equation of an exponential function of the form y = ab^x that passes through the points (3,13.5) and (5,30.375).

User Nerdherd
by
2.9k points

2 Answers

20 votes
20 votes

Let's see

  • y=ab^x

Check coordinates

  • 13.5=ab³-(1)

Find a

  • a=13.5/b³---(2)

And

  • 30.375=ab⁵

Put value from second one

  • 30.375=13.5b⁵/b³
  • 30.375=13.5b²
  • b²=2.25
  • b=1.5

Put in second one

  • a=13.5/b³
  • a=13.5/1.5³
  • a=13.5÷3.375
  • a=4

So the equation is

  • y=4(1.5)^x
User Ken De Guzman
by
3.3k points
19 votes
19 votes

Answer:


y=4(1.5)^x

Explanation:

General form of an exponential function:
y=ab^x

where:

  • a is the y-intercept (or initial value)
  • b is the base (or growth factor)
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

Given ordered pairs:

(3, 13.5) and (5, 30.375)

As the y-values are increasing, the function is increasing, so b > 1

Input the given ordered pairs into the general form of the equation:


\implies ab^3=13.5


\implies ab^5=30.375

To find b, divide the second equation by the first:


\implies (ab^5)/(ab^3)=(30.375)/(13.5)


\implies b^2=2.25


\implies b=\pm √(2.25)


\implies b= \pm 1.5

As the function is increasing, b > 1:

⇒ b = 1.5 only

Substitute the found value of b into one of the equations and solve for a:


\implies a(1.5)^3=13.5


\implies 3.375a=13.5


\implies a=(13.5)/(3.375)


\implies a=4

Therefore, the final exponential equation is:


y=4(1.5)^x

User NetherGranite
by
3.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.