Question

What mass of water will be collected if 20.0

grams of hydrogen are consumed
2H2+O2--->2H2O
358g
179g
44.7g
Or 89.4g

Answer 1

Answer: 179 of
`H_2O` will be produced.

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} H_2=(20.0g)/(2.01g/mol)=9.95moles`

`2H_2+O_2(g)\rightarrow 2H_2O`

According to stoichiometry :

2 moles of
`H_2` give = 2 moles of
`H_2O`

Thus 9.95 moles of
`H_2` will require=
`(2)/(2)* 9.95=9.95moles` of
`H_2O`

Mass of
`H_2O=moles* {\text {Molar mass}}=9.95moles* 18g/mol=179g`

Thus 179 of
`H_2O` will be produced.