How many moles of oxygen are required to react completely with 16.5 mol Al?

Question

asked May 27, 2021 104k views

1 Answer

CharlyDelta · Answer 1 · 2021-05-31T01:11:38+0000

Answer:

12.4 mol O2

Step-by-step explanation:

4Al + 3O2 -----> 2Al2O3

from reaction 4 mol 3 mol

given 16.5 mol x mol

x = 16.5*3/4 =12.4 mol O2