Answer:
![150ft^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/e2d9i7gxin08iist9fp3bxgpd2ikw1nqf2.png)
Explanation:
length:
Convert to an improper fraction.
![(7*2+1)/(2)=(15)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/c21drvpctbl4mnz571wrtyzngik6jehhjs.png)
width:
![5 in](https://img.qammunity.org/2021/formulas/mathematics/high-school/m9uajmmdnmlsltsv6ebbf356clwuqz2xj1.png)
![Formula: A=w*l](https://img.qammunity.org/2021/formulas/mathematics/high-school/3gpbw415qr0ozdct3kd2stxdcerjjoqhyc.png)
![A=(5in)((15)/(2)in)\\A=(75)/(2)in^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/t88umbln6wkyllxru3twwulyvug8slbju2.png)
Convert to ft. I assume your conversion factor is
. However, the unit we need is squared. Square both sides.
![((1)/(2)in.)^2 : (1ft)^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/nhq4op1im4i9id2m4af9r6pfs5ig1mocms.png)
![(1)/(4)in^2 : 1ft^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/8g79furcptrrdvarjfm4nw3vpkx1t6tdvd.png)
Convert.
![(75)/(2)in^2((1ft^2)/((1)/(4)in^2 ) )=](https://img.qammunity.org/2021/formulas/mathematics/high-school/k29vm43tndgut4jilq7itv1t9i8uvsbliv.png)
Invert the fraction in the denominator and multiply it by the numerator.
![(75)/(2)in^2*1ft^2*4in^-^2=75*2ft^2=150ft^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/6ik06j0s4ryg95iciwtjzzu1x8ec51f1ij.png)