Question

This is about Electrostatics

Answer 1

Force,
`F=2.88* 10^(-3)\ N`

Step-by-step explanation:

Charge 1,
`q_1=1* 10^(-7)\ C`

Charge 2,
`q_2=-2* 10^(-7)\ C`

Distance between charges, d = 0.25 m

It is required to find the force between charges. The charges are opposite the force between them is attractive. The force between charges is given by :

`F=(kq_1q_2)/(d^2)\\\\F=(9* 10^9* 1* 10^(-7)* 2* 10^(-7))/((0.25)^2)\\\\F=2.88* 10^(-3)\ N`

So, the force between charges is
`2.88* 10^(-3)\ N`.