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Find the point on the terminal side of θ = negative three pi divided by four that has an x coordinate of -1. Show your work for full credit.

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Answer:

(-1,-1)

Explanation:

x = rcos(theta)

-1 = r cos(-3pi/4)

-1 = r(-sqrt(2)/2)

r = sqrt(2)

y = rsin(theta)

y = sqrt(2)sin(-3pi/4)

y = -1

(-1,-1)

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