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Can anyone help me with this please? Thanks again.

In a picture, a man measures 2.3 cm. His actual height is 1.78 m. He is standing beside a flagpole that measures 7.6 cm in the picture. What is the actual height of the flagpole, to the nearest tenth of a meter?

1 Answer

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Answer:

5.88 meters

Explanation:

This is a problem of scale factor which uses the concept of ratio.

scale factor is the ratio of length of actual figure to length of its model.

Example: if an architect is drawing design for a building

if height of building is 100 meter but he is drawing this on paper of 1 meter then scale factor will 100/ 1= 100: 1.

It means that for every 100 meter of length of building, it can be represented by 1 meter of its model.

Thus if a building has length 200 meter then its model will be of 200/100 = 2 meter length.

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We will solve the given problem based on use of this concept.

Height of man = 1.78 meter

since in picture unit of measure is in cm, lets convert 1.78 meter to centimetre.

1 meter = 100 cm

1.78 meter = 100* 1.78 cm = 178 cm

height of man in picture = 2.3 cm

Scale factor = actual Height of man/Height of man in picture

= 178/2.3 = 77391

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ratio of actual height of flagpole / height of flagpole = actual Height of man/Height of man in picture

Substituting the value given in problem we have

actual height of flagpole/7.6 = 178/2.3

=>actual height of flagpole = (178/2.3)* 7.6 = 588.172 cm.

Thus height of pole is 588.172 cm.

In meter, height of pole is 588.172*100 cm

height of pole is 5.88 meters

User Kirill Savik
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