Question

What is the temperature of an ideal gas if 2.50

moles of the gas occupy a 3.00 liter container
at a pressure of 2500. kPa? Record your answer
to the nearest Kelvin.
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Answer 1

Answer: The temperature of an ideal gas is 360 K

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 2500 kPa = 24.67 atm (1kPa= 0.0098atm)

V = Volume of gas = 3.00 L

n = number of moles = 2.50 mol

R = gas constant =
`0.0821Latm/Kmol`

T = temperature = ?

`T=(PV)/(nR)`

`T=(24.67atm* 3.00L)/(0.0821 L atm/K mol* 2.50mol)=360K`

Thus the temperature of an ideal gas if 2.50 moles of the gas occupy a 3.00 liter container is 360 K