Question

Write an equation in slope-intercept form of the line that passes through the points (−2, 15) and (6, 11)

Answer 1

y =
`-(1)/(2)`x + 14

Explanation:

Slope formula =
`(y2 - y1)/(x2 - x1)`

Slope =
`(11 - 15)/(6 - (-2))`

Slope =
`(-4)/(8)` =
`-(1)/(2)`

Slope intercept: y = mx + b

You can use any coordinate point to use so you can find the y-intercept.

Let's use (6, 11)

11 =
`-(1)/(2)`(6) + b

11 = -3 + b

14 = b

So, the slope intercept form of these points is shown as..

y =
`-(1)/(2)`x + 14