Question

Calculate the [OH], [H30] and pOH given the following:

pH = 12.62

Show ALL work for credit and show the steps used in numerical and word form.​

Answer 1

`[H_3O^+]=2.40x10^(-13)M`

`[OH^-]=0.0417M`

`pOH=1.38`

Step-by-step explanation:

Hello,

In this case, we are able to compute the concentration of hydroxyl and hydronium by using both he pH and the pOH as shown below:

`[OH^-]=10^(-pOH)`

`[H_3O^+]=10^(-pH)`

Moreover, we are able to compute the pOH by:

`pH+pOH=14\\pOH=14-pH=14-12.62=1.38`

So we compute the concentrations:

`[OH^-]=10^(-1.38)=0.0417M`

`[H_3O^+]=10^(-12.62)=2.40x10^(-13)M`

Best regards.