Question

What is the ph of 1.2 time 10 to the negitive 2

Answer 1

Step-by-step explanation:

H⁺ = 1.2 x 10⁻²

pH = - log[H⁺]

= - log [ 1.2 x 10⁻²]

= - log1.2 + 2

= - .079 + 2

= 1.921 .