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Cindy is wrapping a birthday present for her friend.

4 in.
10 in.
5 in.
How much wrapping paper will Cindy need to cover the present?
A 220 sq in.
B 180 sq in.
C 200 sq in.
D 110 sq in.

1 Answer

4 votes

Answer:

220 sq inches

Explanation:

Dimension of present is 4 in,10 in,5 in

Since object has 3 dimension it can be safely assumed that object is rectangular in shape.

total surface area of rectangular object is given by formula

=2 (lb+bh+ hl)

where l , b and h are length , width and height of rectangular object .

Wrapping paper required for present will be equal to total surface areaa of present as paper will be covering the surface area of present.

Thus total surface area of present is = 2*( 4*10+10*5+5*4)

= 2*(40+50+20) = 2*110

= 220

Thus , wrapping paper Cindy needed to cover the present is 220 sq inches.

User Monkey Blot
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