Question

What is the percent-by-mass, %(m/m), concentration of sucrose ( table sugar) in a solution made by dissolving 22.8 g of sucrose in 41.7 g of water

Answer 1

32.6 %

Step-by-step explanation:

Given data

• Mass of sucrose (solute): 22.8 grams

• Mass of water (solvent): 47.1 grams

Step 1: Calculate the mass of the solution

The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.

m(solution) = m(solute) + m(solvent)

m(solution) = 22.8 g + 47.1 g

m(solution) = 69.9 g

Step 2: Calculate the percent-by-mass of sucrose in the solution

We will use the following expression.

`\% m/m = (mass\ of\ sucrose)/(mass\ of\ solution) * 100\% = (22.8g)/(69.9g) * 100\% = 32.6 \%`

Answer 2

`\%m/m=35.3\%`

Step-by-step explanation:

Hello,

In this case, we understand the by-mass percentage as a relationship between the mass of the solute (in this case sucrose) and the mass of the solution (composed by the sucrose and the water):

`\%m/m=\frac{m{solute}}{m_(solution)}*100\%`

Thus, since the solution is composed both both the sucrose and the water, the required percentage results in:

`\%m/m=(22.8g)/(41.7g+22.8g)*100\%\\\\\%m/m=35.3\%`

Best regards.