Answer:
Cost of the car in year 2016 will be $2811.
Explanation:
Cost price of the car = $22800
Value of the car has been depreciating exponentially, so the formula for value of the car after t years,
![P(t)=A(1-(r)/(100))^(t)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nve9xfw11545cp0pyo6f429snzyib5mkxt.png)
Here P(t) = Final value after t years
A = Cost price or initial value
r = rate of depreciation
t = duration in years
![P(6)=22800(1-(r)/(100))^(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mlqncxkys8k6vlud7uibsruil2rhc48aos.png)
![10400=22800(1-(r)/(100))^(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yn3zhov8nhl54lgg22dfs4k4ndj6npapdu.png)
![(10400)/(22800)=(1-(r)/(100))^(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qjtcys5fanjc94yjwdxzlzw441a1khbx61.png)
0.87737 =
r = 100(1 - 0.87737)
r = 12.26%
Now cost of the car in year 2016 (After 16 years)
P(16) =
![22800(1-(12.26)/(100))^(16)](https://img.qammunity.org/2021/formulas/mathematics/high-school/1e9dpoog85b5p5nhblqsghlep8efvnii1t.png)
=
![22800(0.87737)^(16)](https://img.qammunity.org/2021/formulas/mathematics/high-school/octmh14rivyi6d83svmlql15g6p2matn9q.png)
= 2810.99
= $2811
Therefore, cost of the car in year 2016 will be $2811.