Answer:
1. Volume of the composite figure is 943.89 mm³
2. The volume, of the is 144 cm³
Explanation:
1. The composite figure comprises of a cube and a half cylinder;
Volume of a cube = 9 mm × 11 mm × 6 mm = 594 mm³
Volume of the half cylinder = area of base × length = (π·r²)/2 × l
Where:
r = (Diameter of base)/2 = 9/2 = 4.5 mm
l = 11 mm
Therefore, plugging the values, gives;
Volume of the half cylinder = (π × 4.5²)/2 × 11 = 349.89 mm³
Hence, volume of the composite figure = Volume of the cube + Volume of the half cylinder
Volume of the composite figure = 594 mm³ + 349.89 mm³ = 943.89 mm³
2. The volume, V of a pyramid is given by the following relation;
![V = (l * w * h)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/pnvxoe2kd8ag5u7111vx9ilkn0f57yfjbh.png)
Where:
l = Length of base = 8 cm
w = Width of the base = 6 cm
h = Height of the pyramid = 9 cm
![V = (8 * 6 * 9)/(3) = 144 \ cm^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/is8rbztlesed8x2vhj7ymq04q3sb8c2srq.png)
Here we have that a cube of side x, therefore, the area = x·x, integrating we have;
![\int\limits^x_0 {x \cdot x} \, dx = (x^3)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/csir0f1b106moqbwlfahc3q3grcr3urxqt.png)
Where:
Length, height width of the pyramid = x
It can therefore be shown, that for a pyramid of length, l, width, w, and height, h, the volume,
.