Question

Find the particular solution to y ' = 2sin(x) given the general solution is y = C - 2cos(x) and the initial condition y of pi over 2 equals 1 .

-2cos(x)
2 - 2cos(x)
1 - 2cos(x)
-2 - 2cos(x)

I think it is option C. Thank you in advance!

Answer 1

1 − 2 cos x

Explanation:

y' = 2 sin x

y = C − 2 cos x

1 = C − 2 cos(π/2)

1 = C

y = 1 − 2 cos x