Question

Use the discriminant to determine how many real number solutions exist for the quadratic equation −4x2 + 3x –28 = 0.

Question 4 options:

A)

0

B)

3

C)

2

D)

1

Answer 1

A) 0

Explanation:

The discriminant is found by plugging a, b, and c into this formula:

D = b^2 - 4ac

If D > 0, there's 2 solutions.

If D = 0, there's 1 solution.

If D < 0, there's no real solutions.

a = -4, b = 3, and c = -28

D = (3)^2 - 4(-4)(-28)

D = 9 + 16(-28)

D = 9 - 448

D = -439

Since -439 is less than zero, there's no real solutions.