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Find two numbers, if their sum is 49 and their difference is 1/2 .

1 Answer

2 votes

Answer:


x=24(3)/(4)\\ y=24(1)/(4)

Explanation:

Let the two numbers be x and y

So we have:


x +y = 49\\x-y=(1)/(2)

using the elimination method, add the two equations together:


2x=49(1)/(2) \\2x=(99)/(2)

solve for x:


x=(99)/(4)\\x=24(3)/(4)

substitute our value for x back into the first equation we made:


x+y=49\\((99)/(4)) + y=49\\y=49-(99)/(4)\\y=(97)/(4) \\ y=24(1)/(4)

therefore,


x=24(3)/(4)\\ y=24(1)/(4)

User Abhishek Kushwaha
by
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