Question

Find two numbers, if their sum is 49 and their difference is 1/2 .

Answer 1

`x=24(3)/(4)\\ y=24(1)/(4)`

Explanation:

Let the two numbers be x and y

So we have:

`x +y = 49\\x-y=(1)/(2)`

using the elimination method, add the two equations together:

`2x=49(1)/(2) \\2x=(99)/(2)`

solve for x:

`x=(99)/(4)\\x=24(3)/(4)`

substitute our value for x back into the first equation we made:

`x+y=49\\((99)/(4)) + y=49\\y=49-(99)/(4)\\y=(97)/(4) \\ y=24(1)/(4)`

therefore,

`x=24(3)/(4)\\ y=24(1)/(4)`