Question

Calculate the pH of a [0.000765) M solution of KOH

Answer 1

pH=10.88

Step-by-step explanation:

Hello,

In this case, since potassium hydroxide is completely dissociated as shown below:

`KOH\rightarrow K^++OH^-`

For which we understand it is a base, more specifically, a strong base; it means that the concentration of the OH⁻ equals the concentration of the potassium hydroxide, that is 0.000765M, for that reason we can directly compute the pOH:

`pOH=-log([OH^-])=-log(0.000765)=3.12`

Finally, since the pOH and the pH are related by:

`pOH+pH=14`

The pH turns out:

`pH=14-3.12\\pH=10.88`

Best regards.