Question

The pressure of a gas is 100.0 kPa and its volume is 500.0 mL. If the volume increases to 1,000.0 mL, what is the new pressure of the gas?

Answer 1

Using Boyle's Law, which indicates the inverse relationship between pressure and volume, the new pressure of a gas will be 50.0 kPa when its volume increases from 500.0 mL to 1,000.0 mL.

Step-by-step explanation:

The question posed relates to the properties of gases and how they change under varying conditions, specifically volume and pressure. We can understand this relationship using Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature and the amount of gas are held constant. This principle is foundational in the field of physics and is often explored in high school chemistry as well.

Thus, when the volume doubles from 500.0 mL to 1,000.0 mL, the pressure will halve, assuming the temperature and the amount of gas remain constant. The new pressure can be calculated as follows:

Initial pressure (P₁) = 100.0 kPa
Initial volume (V₁) = 500.0 mL
Final volume (V₂) = 1,000.0 mL
Final pressure (P₂) = ?

Using Boyle's Law (P₁V₁ = P₂V₂), we find:

P₂ = P₁V₁ / V2
P₂ = (100.0 kPa) × (500.0 mL) / (1,000.0 mL)
P₂ = 50.0 kPa

Therefore, the new pressure of the gas when the volume is increased to 1,000.0 mL is 50.0 kPa.

Answer 2

`P_2=50kPa`

Step-by-step explanation:

Hello,

In this case, we can apply the Boyle's law in order to understand the pressure-volume relationship as an inversely proportional relationship relating the initial and the final volume:

`P_1V_1=P_2V_2`

Next, we compute the final pressure P2:

`P_2=(P_1V_1)/(V_2)=(100.00kPa*500.0mL)/(1000.0mL) \\\\P_2=50kPa`

Thus we validate, the higher the volume the lower the pressure.

Best regards.