Question

How many grams of H20 will be formed when 32.0 g H2 reacts with 16.0 g

O2? *
2H2 + O2 + 2H2O
9.00 g
16.0 g
18.0 g
32.0g

Answer 1

18.0 g

Step-by-step explanation:

M(H2) = 2.0 g/mol

32.0g * 1 mol/2 g= 16 mol H2

M(O2) = 32 g/mol

16.0 g * 1mol/32 g= 0.5 mol O2

2H2 + O2 ---> 2H2O

from reaction 2 mol 1 mol

given 16 mol 0.5 mol

We see that O2 is a limiting reactant.

2H2 + O2 +-------> 2H2O

from reaction 1 mol 2 mol

given 0.5 mol x mol

x =(0.5*2)/1= 1 mol H2O

M(H2O)= 18 g/mol

18 g/mol* 1 mol = 18 g H2O