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How many moles of NaCl are contained in 100.0ml of a 0.20m solution
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How many moles of NaCl are contained in 100.0ml of a 0.20m solution

User Mauro Torres
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1 Answer

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M= 0.20 M
V= 100.0 ml = 0.100 L
n= ??

M = n/v

:. n = MV

n = 0.20M x 0.1000L

:. n = 0.020 mol
User Robert Mason
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