Question

What is the simplest radical form of
(x-5)^2=98 ?

please help!!!!​

Answer 1

Answer:
`x=7√(2)+5`

Explanation:

`(x-5)^2=98`

Extract the square root on both sides.

`√((x-5)^2)=√(98)`

`x-5=√(98)`

Add 5

`x=√(98)+5`

Simplify the square root.

To do this, find numbers that multiply 98 and repeat so that they can be taken out of the root.

7*7*2 or
`7^2*2`

Replacing this in the root will make a 7 come out of it.

`x=√(7^2*2)+5`

`x=7√(2)+5`