Question

6. Find the partial pressures of the gases in a mixture with a total pressure of 101.3 kPa, if there are 7.8 mole of

Ng, 2.1 mole of 0, 0.090 mole of Ar, and 0.010 mol of Co,
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Answer 1

Step-by-step explanation:

Total mole of gases = 7.8 + 2.1 + .09 + .01 = 10

the partial pressures of the gases in a mixture

= mole fraction x Total pressure

mole fraction = mole of a gas in the mixture / total mole

partial pressure of Ng =
`(7.8)/(10) * 101.3 kPa`

= 79.014 kPa

partial pressure of O =
`(2.1)/(10) * 101.3 kPa`

= 21.273 kPa .

partial pressure of Ar =
`(.09)/(10) * 101.3 kPa`

= .9117 kPa .

partial pressure of Co =
`(.01)/(10) * 101.3 kPa`

= .1013 k Pa .