Question

A collection of 109 coins is made up of quarters, dimes, and nickels. There are 7 fewer dimes than quarters and 3 less than five times as many nickels as dimes. Find the amount of the collection.

If the number of quarters is x, the equation is is [ equation here ]
The amount of collection is $[ answer ]

Answer 1

Equation: x+(x-7)+(5(x-7)-3)=109

Anwser: $9.40

Explanation:

Quarters➡x

Dimes➡x-7

Nickels➡5(x-7)-3

x+(x-7)+(5(x-7)-3)=109

x+x-7+(5x-35-3)=109

x+x+7+5x-35-3=109

7x-31=109

7x=140

x=20

Quarters - 20 (20*25)=500 cents or 5 dollars

Dimes- 13 (13*10)=130 cents or 1 dollar 30 cents

Nickels- 62 (62*5) = 310 cents or 3 dollars and 10 cents

5+1.30+3.10=$9.40

Answer 2

q = quarters; d = dimes; n = nickels

109 = q + d + n

d = q - 7

n = 5d - 3

109 = d + 7 + d + 5d - 3 -->

109 = 7d + 4 -->

105 = 7d -->

15 = d -->

22 = q -->

72 = n -->

.1d + .25q + .05n -->

$1.50 + $5.50 + $3.60 =

$10.60