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Given: OA=AC=2
Line AB is a tangent line
Find: AB

Given: OA=AC=2 Line AB is a tangent line Find: AB-example-1

1 Answer

2 votes

Answer:

AB = 3.464.

Explanation:

Here we are given that OA = AC = 2

Therefore, ΔOAC is an equilateral triangle and ∡OCA = 60°

Therefore, ∡ACB = 120° (sum of angles on a straight line)

Where ∡OAC + ∡CAB = 90° (Angle of a tangent) and ∡OAC = 60° (interior angle of an equilateral triangle) hence, ∡CAB = 30°

Therefore, since ∡OBC + ∡ACB + ∡CAB = 180°, we have;

∡OBC + 120° + 30° = 180°, hence ∡OBC = 30°

From trigonometric ratios, tan(∡OBC) = OA/AB

∴ tan(30°) = 2/AB which gives

AB = 2/(tan(30°) = 3.464

AB = 3.464.

User Aminfar
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