Answer:
![V_2=583.3mL](https://img.qammunity.org/2021/formulas/chemistry/college/k2wg822016hrtm50qv4uihdcu47il804lq.png)
Step-by-step explanation:
Hello,
In this case, for the given constant amount and pressure of the, we apply the Charles' law which allows us to understand the volume-pressure behavior as a directly proportional relationship:
![(V_1)/(T_1) =(V_2)/(T_2)](https://img.qammunity.org/2021/formulas/chemistry/high-school/3ft2qkjxn53q2whj6xhhn65dsivcxc3flk.png)
Thus, since we need to compute the volume after the temperature increase (which must be expressed in absolute Kelvins), we obtain V2 as:
![V_2=(V_1T_2)/(T_1) =(350.0mL*(227+273.15)K)/((27+273.15)K)\\ \\V_2=583.3mL](https://img.qammunity.org/2021/formulas/chemistry/college/ma144zeplnqzuetmh6fl624y4e2s0gd759.png)
Best regards.