Question

PLEASE HELP!! DUE!!!!

Write the slope-intercept form of an equation for the line that passes through the given point and is parallel to the graph of the given equation. (−5, 6) and 12x+9y=3

Answer 1

The equation is,

`y = - (4)/(3)x - (2)/(3)`

Explanation:

When a line is parallel to the other line, they will have the same gradient :

`12x + 9y = 3`

`9y = - 12x + 3`

`y = - (12)/(9) x + (3)/(9)`

`y = - (4)/(3) x + (1)/(3)`

We have already found the gradient. Next, we have to substitute the gradient and coordinates into the slope-form equation, y = mx + b :

`y = mx + b`

Let m = -4/3,

Let x = -5,

Let y = 6,

`6 = - ( 4)/(3) ( - 5) + b`

`6 = (20)/(3) + b`

`b = 6 - (20)/(3)`

`b = - (2)/(3)`