Question

How do I solve this?

Answer 1

The area of the figure is 32 units² .

Explanation:

You can seperate the figures. In this diagram, there 3 triangles and 1 square. Then you have to calculate the area for each shape :

1st triangle (small shape),

`area = (1)/(2) * base * height`

Let base = 2 units,

Let height = 2 units,

`area = (1)/(2) * 2 * 2`

`area = 2 \: \: {units}^(2)`

2nd triangle (medium shape),

Let base = 2 units,

Let height = 6 units,

`area = (1)/(2) * 2 * 6`

`area = 6 \: \: {units}^(2)`

3rd triangle (large shape),

Let base = 10 units,

Let height = 4 units,

`area = (1)/(2) * 10 * 4`

`area = 20 \: \: {units}^(2)`

Square,

`area =base * height`

Let base = 2 units,

Let height = 2 units,

`area = 2 * 2`

`area = 4 \: \: {units}^(2)`

Lastly, you have to add up all the area of the shapes :

`area = 2 + 6 + 20 + 4`

`area = 32 \: \: {unit}^(2)`

Answer 2

We'll solve that in parts.

The upper part is a right triangle that is 4 by (2 + 2 +6)

Area = (4 * 10) /2 = 20

The bottom of that figure is made of 3 parts.

A) a 2 by 2 right triangle. area equals (2*2)/2 = 2

B) a 2 by 2 square whose area equals 2*2 = 4

C) a 6 by 2 right triangle whose area equals (6*2) / 2 = 6

Total Area = 20 + 2 + 4 + 6 = 32

Explanation: