Answer:
How much force is required to accelerate a 1000 kg car from a speed of zero to 27 m/s in 6 seconds?
Here we assume that the co- efficient of static force of friction is negligible for the surface , and write the given data as under,
initial velocity of the car =Vi = 0
final velocity of the car = Vf = 27 m /sec.
time required for the change in velocity = t = 6 sec.
mass of the car = m= 1000 kg
Force required to bring this change in velocity = F= ?
first we find acceleration = a = Vf - Vi / t
= 27 - 0 / 6 = 27 /6 = 4.5 m /sq.sec. = 4.5 N / kg
Now, by Newton`s 2nd law of motion,
F = ma = (1000 kg) x (4.5 N/kg) = 4500 N