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Log3(5x+1)=4 A.) x = 5 B.) x = 16 C.) x = 4 D.) x = 3

User Ebassi
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1 Answer

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Answer:

B) x=16

Explanation:

The 3 is the base, the expression in the parenthesis is the argument and the 4 is the exponent

We also know that
base^(exponent) = argument

so therefore the new equation is
3^(4) = 5x+1

3 to the fourth power is 81

so 81=5x+1

then solve algebraically

User Ilonpilaaja
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