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Write the equation of the line in slope-intercept form of the line that passes through the points (1,6) and (3,-4).

A. y=11x-5
B. y=3x-4
C. y=x+6
D. y=-5x+11

User Jleck
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1 Answer

3 votes

Answer:

Option D

Explanation:

Slope-intercept form is:
y=mx+b

We first need to find the slope of the line with the points (1,6) and (3, -4).


\text {Use the slope formula: }\\m = (y_2-y_1)/(x_2-x1) =(-4-6)/(3-1) = (-10)/(2) = -5

The slope (or m) is -5.

With this information, we can eliminate A, B, and C, because in the equation the slope is not -5.

D looks promising. Let's make sure that it is correct by finding the y-intercept.


y = -5x + b\\\text {Using the point: (1,6)}\\\\\rightarrow 6 = -5(1) + b\\\\6 = -5 + b\\6+5 = (-5 + 5) +b\\11 = b

The y-intercept is 11.

So, the equation of the line in slope-intercept form of the line that passes through the points (1,6) and (3,-4) should be
y=-5x+11, or Option D.

User Scalopus
by
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