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What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form?

x = -4+213
x= -4 = 48
x= -85
323
x = -414,3
2

User DinhNguyen
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1 Answer

5 votes

Answer:

-4 ± 2*sqrt(3)

Explanation:

Well I'm not quite sure as to what the x= equations are, but for the solution to this quadratic I just used the quadratic formula. This gave me -8 ± sqrt(48)/2, which can be simplified to -4 ± 2 * sqrt(3). Hope this helps :)

User Victor Ejiogu
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