Question

I need help pleaseeee

Answer 1

Follow the Pythagoreas theorm. You typically need to find
`C^2`, which is the hypotonuse, but because we already know this, we can rearrange the equation to make sense.

Personally, I like to substitute with non-related numbers, such as 1 and 2. In the following example, the sides are 1 unit, 2 units, and 5 units. First, I like to figure out the sum of
`a^2` and
`b^2` .

EX:
`1^2+2^2= 5`

`25^2=5`

I can rearrange this so that one leg and the hypotenuse are on the same side:

`25^2-1^2=2^2`

Now I can take out the example numbers, and substiture in the variables.

`c^2-a^2=b^2`

Now all I have to do is fill in the known variables!

`15^2-12^2=b^2`

Solve!

`225-144=80`

We're not done- we have to find the square root of 81!

It's 9m!

Finally, we can check our work by plugging
`A^2` and
`B^2` into the normal equation. It checks out!

`12^(2) +9^(2) = 15^(2) \\=225 =225\\225=225`

Have questions? Let me know!

Answer 2

Third side is 9m.

Explanation:

In a right triangle the square on the hypotenuse is equal to the sum of the squares on the other two sides.

15 x 15= 225m2

12 x 12 = 144m2

225 - 144 = 81m2 and the length of the third side is square root of 81, which would be 9m as your final answer.