Question

A container is filled with 10 mol of gas and the pressure (Pi) is measured. If 5 mol are removed, what is the new pressure (Pf)?

Answer 1

1/2 of the Pi

Step-by-step explanation:

PV = nRT

we are going to assume the only things changing are pressure and number of mols, so we change the formula and substitute the variables to make it what we are looking for

`(Pi)/(ni) = (Pf)/(nf)`

then we will assume Pi as 1 as it is not given, so we can state it easier

`(1atm)/(10mol) = (xatm)/(5mol)`

then either cross multiply or just work it out to be

`(1)/(2)` which we can say as "half of the initial pressure" as no number is given for initial pressure