Question

What is the equation of the line that passes through the points (1, –1) and (3, –7)

Answer 1

y = -3x + 2

Explanation:

To find the slope of an equation you can do (y2-y1)/(x2-x1). Plug the values in from the equation and you get (-1+7)/(1-3), or 6/-2. This means the slope is -3. Then you plug the values of y and x into an equation y = -3x + b, and you get -1 = (-3)1 + b. Solve for b. -1 = -3 + b, (add 3 to each side) 2 = b. Then plug b back into your equation and you get y = -3x + 2

Answer 2

-3x+2=y

Explanation:

u need to find the slope intercept formula which mx+b=y

m=slope

b=y-intercept

first u should find the slope which is y2-y1/x2-x1

point 1:(1,-1)

point 2:(3,-7)

-7+1/3-1=-6/2=-3

m=-3

now replace the variables

-3(1)+b=-1

-3 times 1=-3

-3+b=-1

add 3 to both sides

b=2

now the equation is -3x+2=y