Register
3. What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated? (Specific heat of water is 4.184 J/g °C)​
216k views
2 votes
3. What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?

(Specific heat of water is 4.184 J/g °C)​

User Hal
by
8.3k points

1 Answer

3 votes

Answer:

20.076°C

Step-by-step explanation:

Q = mcΔT

ΔT =
(Q)/(mc)

ΔT =
(840J)/(10g * 4.184J/gC)

ΔT = 20.076°C

User Salar Bahador
by
8.0k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
Why is gold preferred as a superior metal over silver and bronze?
What is the evidence of a chemical reaction when the fireworks go off
Link Copied!