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3. What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated? (Specific heat of water is 4.184 J/g °C)​
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3. What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?

(Specific heat of water is 4.184 J/g °C)​

User Hal
by
8.3k points

1 Answer

3 votes

Answer:

20.076°C

Step-by-step explanation:

Q = mcΔT

ΔT =
(Q)/(mc)

ΔT =
(840J)/(10g * 4.184J/gC)

ΔT = 20.076°C

User Salar Bahador
by
8.0k points
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