Question

what is the probability that a data value and a normal distribution is between a z score -1.32 and a z score of 0.94

Answer 1

0.733

Explanation:

Using a calculator or table:

P(-1.32 < Z < 0.94) = P(Z < 0.94) − P(Z < -1.32)

P(-1.32 < Z < 0.94) = 0.8264 − 0.0934

P(-1.32 < Z < 0.94) = 0.733