Question

Find the solutions to the equation (-3y)(6y)+9=0​

Answer 1

`y=\pm\text{ }i\sqrt{(1)/(2)}`

Explanation:

So we first multiply out the parentheses, which turns out to be
`-18y^2`. So our equation is
`-18y^2 + 9 = 0`. We factor out a 9, which turns into
`9(2y^2+1)`. So
`2y^2+1=0.` Solving, we have
`y^2=-(1)/(2)`, and
`y=\pm\text{ }i\sqrt{(1)/(2)}`. I'm sorry everything is so messy, I hope you can still understand.